√2(sinx*cosπ/4-cosx*sinπ/4)不等于0能得到√2sin(x-π/4)不等于0
√2(sinx*cosπ/4-cosx*sinπ/4)不等于0能得到√2sin(x-π/4)不等于0
sinx-cosx不等于0怎么推出来根号2倍的sin(x-4/π)不等于0的?
怎么样由sinα不等于cosα推导出根号2sin[x-(4/π)] 不等于0
证明x∈(0,π/2),cos(cosx)>sin(sinx)
sinx+cosx=√2sin(x+π/4)
已知函数y=(sinx+cosx)^2+2cos^x 咋求最大值最小值.化简得到=2+√2sin(2x+π/4)详细解!
已知sinx+cosx/sinx-cosx=2,求2cos(π-x)-3sin(π+x)/4cos(-x)+sin(2π
已知sin(kπ+x)=-2cos(kπ+x)求(4sinx-2cosx)÷(5cosx+3sinx),和4sin&su
如何得到f(x)=|sinx+cosx|=|根号2sin(x+π/4)|?
求证sinx-cosx=根号2sin(x-π/4)
y=cosx+sinx=√ 2(√ 2/2sinx+√ 2/2cosx)为什么=√ 2(cos π/4sinx+sin
化简sin^4x/sinx-cosx - (sinx+cosx)cos^2x/tan^2x-1