已知2x-y=10,求式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/12 00:03:11

[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y
=[(x^2+y^2)-(x^2-2xy+y^2)+2xy-2y^2]/4y
=[x^2+y^2-x^2+2xy-y^2+2xy-2y^2]/4y
=(4xy-2y^2)/4y
=2y(2x-y)/4y
=(2x-y)/2
=10/2
=5

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