a,b为常数.lim（n->无穷）an^2+bn+2/2n-1=3 求a,b

a,b为常数.lim（n->无穷）an^2+bn+2/2n-1=3 求a,b 已知lim n→无穷 （an^2+bn+5）/(3n-2)=2,求a,b的值 已知lim[(3n^2+cn+1)/(an^2+bn)-4n]=5,求常数a、b、c的值 lim (n→∞) [(an^2+bn+c)/(2n+5)]=3,求a,b 若lim n->无穷 [ 2n^2/(n+2) - an ]=b,求常数a,b的值 求过程,感谢.. lim[{根号(n^2+an)}-(bn+1)]=b,求a 已知a b 是常数 lim（a根号（2n^2+n+1) -bn))=1 则a+b= 若lim[2n+(an^2+2n+1)/(bn+1)=1,则a+b lim[2n+(an^2-2n+1)/(bn+2)]=1,则点(a,b)坐标为 若lim(2n+(an^2-2n+1)/(bn+2))=1 求a/b的值 已知a,b,为常数,且an=3(n-1)次方-2a(n-1)（1）设bn=an/3的n次方-1/5,证明数列bn为等比数 等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn