解个方程：X^3+2X^2+X+4/27=0

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/13 01:53:22

X^3+2X^2+X+4/27=(X^3+1/27)+(2X^2+X+1/9)
=(X+1/3)(X^2-X/3+1/9)+(X+1/3)(2X+1/3)
=(X+1/3)(X^2+5X/3+4/9)
=(X+1/3)(X+1/3)(X+4/3)
=(X+1/3)^2(X+4/3)
∴(X+1/3)^2(X+4/3)=0
X+1/3=0或X+4/3=0
X=-1/3或X=-4/3

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