①[1-1/(x-1)][x/(x+1)+1]÷[1-3x/(1-x^2)] ②计算:[x^2-4/(x^2-4x+4)
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/10/09 00:49:51
①[1-1/(x-1)][x/(x+1)+1]÷[1-3x/(1-x^2)] ②计算:[x^2-4/(x^2-4x+4)-x-2/(x+2)]÷x/(x-2)
③2/(a+1)-a-2/(a^2-1)÷a^2-2a/(a^2-2a+1)
③2/(a+1)-a-2/(a^2-1)÷a^2-2a/(a^2-2a+1)
①[1-1/(x-1)][x/(x+1)+1]÷[1-3x/(1-x^2)]
=[(x-1-1)/(x-1)][(x+x+1)/(x+1)]÷[(1-x^2-3x)/(1-x^2)]
=[(x-2)/(x-1)][(2x+1)/(x+1)]÷[(1-x^2-3x)/(1-x^2)]
=[(2x^2+x-4x-2)/(x^2-1)]*[(1-x^2)/(1-x^2-3x)]
=[(2x^2-3x-2)/(x^2-1)]*[-(x^2-1)/(1-x^2-3x)]
=-(2x^2-3x-2)/(1-x^2-3x)
=(2x^2-3x-2)/(x^2+3x-1)
②计算:[x^2-4/(x^2-4x+4)-x-2/(x+2)]÷x/(x-2)
=[(x+2)(x-2)/(x-2)^2-x-2/(x+2)]÷x/(x-2)
=[(x+2)/(x-2)-x-2/(x+2)]÷x/(x-2)
=[((x+2)^2-(x-2)^2)/(x-2)(x+2)] *(x-2)/x
=[((x+2)+(x-2))((x+2)-(x-2))/(x-2)(x+2)] *(x-2)/x
=[2x*4/(x-2)(x+2)] *(x-2)/x
=8/(x+2)
③2/(a+1)-a-2/(a^2-1)÷a^2-2a/(a^2-2a+1)
=2/(a+1)-a-2/(a+1)(a-1)* (a-1)^2/a(a-2)
=2/(a+1)-(a-1)/a(a+1)
=(2a-(a-1))/a(a+1)
=(a+1)/a(a+1)
=1/a
=[(x-1-1)/(x-1)][(x+x+1)/(x+1)]÷[(1-x^2-3x)/(1-x^2)]
=[(x-2)/(x-1)][(2x+1)/(x+1)]÷[(1-x^2-3x)/(1-x^2)]
=[(2x^2+x-4x-2)/(x^2-1)]*[(1-x^2)/(1-x^2-3x)]
=[(2x^2-3x-2)/(x^2-1)]*[-(x^2-1)/(1-x^2-3x)]
=-(2x^2-3x-2)/(1-x^2-3x)
=(2x^2-3x-2)/(x^2+3x-1)
②计算:[x^2-4/(x^2-4x+4)-x-2/(x+2)]÷x/(x-2)
=[(x+2)(x-2)/(x-2)^2-x-2/(x+2)]÷x/(x-2)
=[(x+2)/(x-2)-x-2/(x+2)]÷x/(x-2)
=[((x+2)^2-(x-2)^2)/(x-2)(x+2)] *(x-2)/x
=[((x+2)+(x-2))((x+2)-(x-2))/(x-2)(x+2)] *(x-2)/x
=[2x*4/(x-2)(x+2)] *(x-2)/x
=8/(x+2)
③2/(a+1)-a-2/(a^2-1)÷a^2-2a/(a^2-2a+1)
=2/(a+1)-a-2/(a+1)(a-1)* (a-1)^2/a(a-2)
=2/(a+1)-(a-1)/a(a+1)
=(2a-(a-1))/a(a+1)
=(a+1)/a(a+1)
=1/a
如何计算 (x+1)(x+2)(x+3)(x+4)
计算(X-1)(X-2)(X-3)(X-4)
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
计算:2x/(x-2)(x+1)÷(1-x/x+1)-x²+2x/x²-4?
计算:(x-1)(x^2-4X+3)-x(x^2-5X+2)有过程
x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
x^2-1/x^2+4x+4÷(x+1)×x^2+3x+2/x-1计算
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
①[1-1/(x-1)][x/(x+1)+1]÷[1-3x/(1-x^2)] ②计算:[x^2-4/(x^2-4x+4)