一道GMAT数学题.A right circular cone is inscribed in a hemisphere
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一道GMAT数学题.
A right circular cone is inscribed in a hemisphere so
that the base of the cone coincides with the base of
the hemisphere.What is the ratio of the height of the
cone to the radius of the hemisphere?
(A)根3:1
(B) 1:1
(C) 1/2:1
(D) 根2:1
(E) 2:1
A right circular cone is inscribed in a hemisphere so
that the base of the cone coincides with the base of
the hemisphere.What is the ratio of the height of the
cone to the radius of the hemisphere?
(A)根3:1
(B) 1:1
(C) 1/2:1
(D) 根2:1
(E) 2:1
B
right circular cone 那种正圆锥,从圆锥顶点到地面圆心的那条线就是高,这条高跟圆锥底面垂直.
现在这个圆锥在半球中内接,也就是说,圆锥的顶点在半球的表面.而且告知圆锥地面跟半球底面重合,所以两个圆心重合.所以圆锥的高其实就是从半球的圆心到半球表面之间的距离,那个不就是半球的半径么?
所以就是1:1
right circular cone 那种正圆锥,从圆锥顶点到地面圆心的那条线就是高,这条高跟圆锥底面垂直.
现在这个圆锥在半球中内接,也就是说,圆锥的顶点在半球的表面.而且告知圆锥地面跟半球底面重合,所以两个圆心重合.所以圆锥的高其实就是从半球的圆心到半球表面之间的距离,那个不就是半球的半径么?
所以就是1:1
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