两道初中数学题(1)化简分式(x^2-1/x^2+2x+1)-(x+1/x-1)
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/10/05 06:32:37
两道初中数学题(1)化简分式(x^2-1/x^2+2x+1)-(x+1/x-1)
(2)解方程(x-1/x)-(x/x-1)=5/2
(2)解方程(x-1/x)-(x/x-1)=5/2
(1)化简分式(x^2-1/x^2+2x+1)-(x+1/x-1)
=(x+1)(x-1)/(x+1)^2-(x+1)/(x-1)
=(x-1)/(x+1)-(x+1)/(x-1)
=[(x-1)^2-(x+1)^2]/(x+1)(x-1)
=-4x/(x+1)(x-1)
(2)解方程(x-1/x)-(x/x-1)=5/2
(x-1)^2-x^2=5/2x(x-1)
-2x+1=2.5x^2-2.5x
2.5x^2-0.5x-1=0
5x^2-x-2=0
x^2-x/5=2/5
(x-1/10)^2=2/5+1/100=41/100
x-1/10=(+/-)根号41/10
X1=(1+根号41)/10
X2=(1-根号41)/10
检验,X1,X2是方程的根.
=(x+1)(x-1)/(x+1)^2-(x+1)/(x-1)
=(x-1)/(x+1)-(x+1)/(x-1)
=[(x-1)^2-(x+1)^2]/(x+1)(x-1)
=-4x/(x+1)(x-1)
(2)解方程(x-1/x)-(x/x-1)=5/2
(x-1)^2-x^2=5/2x(x-1)
-2x+1=2.5x^2-2.5x
2.5x^2-0.5x-1=0
5x^2-x-2=0
x^2-x/5=2/5
(x-1/10)^2=2/5+1/100=41/100
x-1/10=(+/-)根号41/10
X1=(1+根号41)/10
X2=(1-根号41)/10
检验,X1,X2是方程的根.
两道初中数学题(1)化简分式(x^2-1/x^2+2x+1)-(x+1/x-1)
一道初中数学题(有关分式的) 2x(x+1)(x-1)-x(x+1)(x-1) 三人行,必有我师焉 .
(1)化简分式(x^2-1/x^2+2x+1)-(x+1/x-1)
化简分式【(x/x-1)-(x/x²-1)】÷(x²-x/x²-2x+1),并从-1≤x≤
分式混合计算(x+1/x^2-x - x/x^2-2x+1)*x
一道分式数学题、已知x^2+x-1=0、求x-[1-2/(1-x)]/(x+1)-[x(x^2-1)]/x^2-2x+1
分式化简:(1)1/x-1/(X+1) (2)1/x(x+1)+1/(X+1)(x+2)+...+1/(x+999)(x
解分式方程:2x+1x
分式化简:[(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]/(x-4)/(x^3-2x^2)
2道分式计算[(x+4)(x-2)]/x³+2x²+x÷[(x-2)/x·(x+4)/(x+1)]2
若分式x^2\(x^2+x)化简得X\(X+1).求x应满足的条件
分式通分:x+1/3x,x/2x+6,x-1/x^2-9