2-x/x²-9(1+2x-7/x²-4x+4)÷1/x+3

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/18 15:16:28

(2-x)/(x²-9)[1+(2x-7)/(x²-4x+4)]÷1/(x+3)
=(2-x)/[(x+3)(x-3)](x²-2x-3)/(x-2)²×(x+3)
=1/(x-3)×(x²-2x-3)/(x-2)
=1/(x-3)×(x-3)(x+1)/(x-2)
=(x+1)/(x-2)

(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| 2-x/x²-9(1+2x-7/x²-4x+4)÷1/x+3 (2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3) 计算:2x/(x-2)(x+1)÷(1－x/x+1)-x²+2x/x²-4? [（x+2）/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1 设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10), 4x²-1/3x²-x·9x³-x/2x^4-x³计算急（1） x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8 X+7/X+1+X+8/X+2-X+9/X+3-X+10/X+4 的解法 x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)