sin(α+π/3)+sinα= -4根号3分之5,-π/2<α<0,则cosα=?
sin(α+π/3)+sinα= -4根号3分之5,-π/2<α<0,则cosα=?
已知:sin(α+π/3)+sinα=负5分之4根号3 α∈(-π/2,0)求cosα
sin(α+π/3)+sinα=负5分之4根号3 α∈(-π/2,0)求cosα
sin(α-4分之π)分之cos2α=—2分之根号2 求cosα+sinα
已知cos(α-π/6)+sinα=4/5 根号3,则sin(α+7/6π)=?
已知sin(π-α)-cos(π+α)=根号2分之4,求sin(π+α)+cos(3π-α)的值
已知tanα=2,sinα+cosα<0,求[sin(2π-α)*sin(π+α)*cos(-π+α)]/[sin(3π
sin(α+π/3)+sinα=负2分之根号3 α∈(-π/2,0)求cosα
2sinα-cosα=根号3sinα,则cosα
若(sinα+cosα)/(sinα-cosα)=2 则sin(α-5π)·sin(3π/2-α)=?
若sinα+cosαsinα−cosα=2,则sin(α-5π)•sin(3π2-α)等于( )
α属于(0,π/2)且2sin²α-sinαcosα-3cos²α=0求sin(α+π/4)/sin