x+2/x+3-x+1/x+2=x+8/x+9-x+7/x+8
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/09/20 23:19:25
x+2/x+3-x+1/x+2=x+8/x+9-x+7/x+8
(x+2)/(x+3)-(x+1)/(x+2)=(x+8)/(x+9)-(x+7)/(x+8)
(x+2)²/[(x+2)(x+3)]-(x+1)(x+3)/[(x+2)(x+3)]=(x+8)²/[(x+8)(x+9)]-(x+7)(x+9)/[(x+8)(x+9)]
[(x+2)²-(x+1)(x+3)]/[(x+2)(x+3)]=[(x+8)²-(x+7)(x+9)]/[(x+8)(x+9)]
(x²+4x+4-x²-4x-3)/[(x+2)(x+3)]=(x²+16x+64-x²-16x-63)/[(x+8)(x+9)]
1/[(x+2)(x+3)]=1/[(x+8)(x+9)]
(x+2)(x+3)=(x+8)(x+9)
x²+5x+6=x²+17x+72
5x-17x=72-6
-12x=66
x=-5.5
经检验 x=-5.5是原方程的根.
(x+2)²/[(x+2)(x+3)]-(x+1)(x+3)/[(x+2)(x+3)]=(x+8)²/[(x+8)(x+9)]-(x+7)(x+9)/[(x+8)(x+9)]
[(x+2)²-(x+1)(x+3)]/[(x+2)(x+3)]=[(x+8)²-(x+7)(x+9)]/[(x+8)(x+9)]
(x²+4x+4-x²-4x-3)/[(x+2)(x+3)]=(x²+16x+64-x²-16x-63)/[(x+8)(x+9)]
1/[(x+2)(x+3)]=1/[(x+8)(x+9)]
(x+2)(x+3)=(x+8)(x+9)
x²+5x+6=x²+17x+72
5x-17x=72-6
-12x=66
x=-5.5
经检验 x=-5.5是原方程的根.
x+2/x+3-x+1/x+2=x+8/x+9-x+7/x+8
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
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1X?+2X?+3X?+4X?+5X?+6X?+7X?+8X?+9X?+10X?=1980求?是多少
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