初一因式分解试题①32a(x^2+x)^2+2a②16+8(x^2+4x)+(x^2+4x)^2③3x^(n)y+9x^
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初一因式分解试题
①32a(x^2+x)^2+2a
②16+8(x^2+4x)+(x^2+4x)^2
③3x^(n)y+9x^(n-1)y^2+1/4x^(n+1)
①32a(x^2+x)^2+2a
②16+8(x^2+4x)+(x^2+4x)^2
③3x^(n)y+9x^(n-1)y^2+1/4x^(n+1)
① 题目有点问题,应该是-2a,不然没法分解了
32a[(x^2+2x)^2]-2a
=2a[16(x^2+2x)^2-1]
=2a(4x^2+8x+1)(4x^2+8x-1)
②
16+8(x^2+4x)+(x^2+4x)^2
=(4+x^2+4x)^2
=(x^2+4x+4)^2
=(x+2)^4
③
3x^ny+9x^(n-1)y^2+x^(n+1)/4
=x^(n-1)(3xy+9y^2+x^2/4)
=x^(n-1)(x^2/4+3xy+9y^2)
=x^(n-1)(x/2+3y)^2
=(1/4)[x^(n-1)](x+6y)^2
32a[(x^2+2x)^2]-2a
=2a[16(x^2+2x)^2-1]
=2a(4x^2+8x+1)(4x^2+8x-1)
②
16+8(x^2+4x)+(x^2+4x)^2
=(4+x^2+4x)^2
=(x^2+4x+4)^2
=(x+2)^4
③
3x^ny+9x^(n-1)y^2+x^(n+1)/4
=x^(n-1)(3xy+9y^2+x^2/4)
=x^(n-1)(x^2/4+3xy+9y^2)
=x^(n-1)(x/2+3y)^2
=(1/4)[x^(n-1)](x+6y)^2
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