已知全集U={1,2,3,4,5},M∩N={5},Cu(M∩N)={4},CuM∩CuN={1,2}

已知全集U={1,2,3,4,5},M∩N={5},Cu(M∩N)={4},CuM∩CuN={1,2} 1 已知全集u{1,2,3,4,5,6},集合m={1,3,5},n={2,4,6},则CuM∩N=N,为什么? 已知集合M=（-3,5],N=[-5,5),若全集U=[-5,a],且（CuM)∩(CuN)=(5,a],求a% 已知全集U=R,M={x丨{3-x＞0,5-≤4},N=｛x丨-2＜x≤3｝求①MUN和M∩N；②M∩（CuN）和（Cu 设全集U=M∪N=﹛1,2,3,4,5﹜,M∩CuN=﹛2,4﹜,则N=（ 已知全集U={x|x为不大于20的质数},M.N是U的两个子集,且满足:M∩(CuN)={3,5},(CuM)∩N={7 若全集U={1,2,3,4,5,6},M={2,3},N={1,4},则集合N∩(CuM)等于( ) 已知全集U=R,集合M={x丨x≤3},N={x丨x<1},求m交n,(cum)并N,(cum)交（cun) 已知集合M=（-3,5],N=[-5,5),若全集U=[-5,a],且（CuM)∩(CuN)=(5,a],求a的取值范围 设集合M={y│-1≤y≤2},N={y│y≥0}全集U=R,求（CuM）交（CuN）. 设全集U={0,1,2,3},集合M={0,1,2},N={0,2,3},则M∩CuN=( ) 已知集合U=R,M=｛x|x-5＜0｝,N =｛x|x+1/x-1＜0｝,求CuM交集CuN