已知集合M=(-3,5],N=[-5,5),若全集U=[-5,a],且(CuM)∩(CuN)=(5,a],求a%
已知集合M=(-3,5],N=[-5,5),若全集U=[-5,a],且(CuM)∩(CuN)=(5,a],求a%
已知集合M=(-3,5],N=[-5,5),若全集U=[-5,a],且(CuM)∩(CuN)=(5,a],求a的取值范围
已知全集U={1,2,3,4,5},M∩N={5},Cu(M∩N)={4},CuM∩CuN={1,2}
已知全集U={x|x为不大于20的质数},M.N是U的两个子集,且满足:M∩(CuN)={3,5},(CuM)∩N={7
已知集合U=R,M={x|x-5<0},N ={x|x+1/x-1<0},求CuM交集CuN
已知U为全集,集合M,N是U的子集,若M∩N=N,则正确的是A.(CuM)包含(CuN) B.M含于(CuN) C.(C
已知全集U=R,集合M={x丨x≤3},N={x丨x<1},求m交n,(cum)并N,(cum)交(cun)
1 已知全集u{1,2,3,4,5,6},集合m={1,3,5},n={2,4,6},则CuM∩N=N,为什么?
若全集U={1,2,3,4,5,6},M={2,3},N={1,4},则集合N∩(CuM)等于( )
设全集U={a,b,c,d,e},集合M={a,b,c},N={b,d,e},那么(CuM)交(CuN)是()麻烦讲一下
设集合M={y│-1≤y≤2},N={y│y≥0}全集U=R,求(CuM)交(CuN).
已知全集U={x|x∈N,且x≤5},A={x|x²-5x+a=0,x∈U},求集合CuA