求证:2(1-sin@)(1+cos@)=(1-sin@+cos@)2
求证:sin^2/(sin-cos) - (sin+cos)/(tan^2 -1) =sin+cos
求证sinθ/(1+cosθ)+(1+cosθ)/sinθ=2/sinθ
求证:(1+cosθ+cosθ/2) /(sinθ+sinθ/2)=sinθ/1-cosθ
求证(1+sinα+cosα+2sincosα)/(1+sinα+cosα)=sinα+cosα
求证sin^2α+sin^2β-sin^2αsin^2β+cos^2cos^2β=1
求证(1-sinθcosθ)除以(cos^2θ-sin^2θ)=(cos^2θ-sin^2θ)除以(1+2sinθcos
求证:(cosβ/(1+sinβ))-(sinβ/(1+cosβ))=(2cosβ-2sinβ)/(1+sinβ+cos
求证(1+sinθ+cosθ)/(1+sinθ-cosθ)+(1-cosθ+sinθ)/(1+cosθ+sinθ)=2/
求证 1+sinα+cosα+2sinαcosα / 1+sinα+cosα = sinα+cosα 能不能用
求证:2(1+sinα)(1+cosα)=(1+sinα+cosα)^2
求证:2(1-sin@)(1+cos@)=(1-sin@+cos@)2
求证:2(1-sinα)(1+cosα)=(1-sinα+cosα)²