sin（π/4-3x）cos(π/3-3x)- sin（π/4+3x）sin(π/3-3x)=

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/18 23:52:37

sin（π/4-3x）=sin[π/2-(π/4+3x)]
=cos(π/4+3x)
sin（π/4-3x）cos(π/3-3x)- sin（π/4+3x）sin(π/3-3x)
=cos(π/4+3x)cos(π/3-3x)- sin（π/4+3x）sin(π/3-3x)
=cos(π/4+3x+π/3-3x)=cos(π/4+π/3)
=√2/2*1/2-√2/2*√3/2
=(√2-√6)/4

化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 已知函数f(x)=cos(2x-π/3）+2sin(x-π/4）sin(x+π/4)=sin(2x-π/6) , sin（π/4-3x）cos(π/3-3x)- sin（π/4+3x）sin(π/3-3x)= 已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4) f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+/4π) 三角函数已知函数f(x)=sin^2*x-根号3*sinπ/4*x*cosπ/4*x 函数y=【cos（3x+π/4)-sin(3x+π/4）】/[cos（3x+π/4)+sin(3x+π/4）]的定义域, 1.y=cos^4x+sin^4x 求周期 2.y=（sin2x+sin（2x+π/3)）/（ cos2x+cos（2x f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx 求化简数学公式哦[3sin^2（x/2）+cos^2（x/2)-4sin(x/2)cos(x/2)]/tan(π+x）化已知函数f(x)= [sin(2π-x)sin(π+x)cos(-x-π)] ／[2cos(π-x)sin(3π-x)] 证明sin^2(x)+cos^2(x+30)+sin(x)cos(x+30)=3/4