新手 matlabA =1 2 3 35 6 7 89 10 11 1213 14 15 16>> syms c;>>

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新手 matlab
A =
1 2 3 3
5 6 7 8
9 10 11 12
13 14 15 16
>> syms c;
>> A(:,1)=c*A(:,1)
The following error occurred converting from sym to double:
Error using ==> mupadmex
Error in MuPAD command:DOUBLE cannot convert the input expression into a double array.
If the input expression contains a symbolic variable,use the VPA function instead.
>>

按照提示修改就行了,赋值类型错误了；不知道你的目的,A(:,1)=c*A(:,1)改为B=c*A(:,1)就可行了

新手 matlabA =1 2 3 35 6 7 89 10 11 1213 14 15 16>> syms c;>> matlab符号矩阵syms a b c dk=[];kk=[];XX=[1 2 3 4];for i=1:1:4;fo matlab .* syms yc;syms yt;x=0:0.001:1;yc=(15.957/6.*(x.^3-3. 求教 matlaba(2,2,2)=1;>> for i=1:2;for j=1:2;for k=1:2;a(i,j,k matlab >> syms x y a b l m1 m2;y =1/2*b+1/2*a-1/6*3^(1/2)*l; matlab符号表达式求解：syms x y; m=x+y+1; x=[1 2 3]; y=[4 5 6]; 请问怎么求 matlab符号计算syms s1 s2 t f ps1=solve('2*3^(1/2)*cos(t)*sin(f)- Matlab新手,已知A=[1 2 3 4 5 6]；怎么使两项相加得到B=[3 7 11]. matlab t=linspace(0,pi/10,1000); >> syms x y z% >> th=[x*(1+ matlab求积分syms x; a=int(1/(1-x^2)*(log(1+x)-log(1-x)); a matlab >> syms r x>> limit(-1/216*a*(36*r^3*exp(-6*r/a)+18*r 为什么在matlab中输入syms x f=sym('x/(cos(x))^2') y(1)=diff(f)