AB+DF+CD+BC=AB+B
AB=CD,AE垂直BC,DF垂直BC,CE=BF,求证AE=DF
如图,AD=BC,AB=CD,DE=BF,试说明DF=BC.
如图,AB=CD,AE⊥BC,DF⊥BC,CE=BF.求证:AE=DF.
如图ab=ae,bc=ae 角bc=de 角b=角e cf=df 求证 af垂直cd
如图,AB=BC=CD=DE=EF=DF,∠MEF=?
如图,已知AB=CD,AD=BC,DE=BF,说明BE=DF
已知:如图,AD=BC,AB=CD,DE=BF求证:BE=DF
已知:如图,AB=CD,BC=DA,AE=CF.求证:DF=DE
如图,ad=bc,ab=cd,de=bf,说明df=be
已知如图,AB+AD=BC+CD,求证BF+DF=BE+DE
已知BC,EF交点O,AB//CD,OA=OD,AE=DF,求证BE//CF
如图,AB=CD,AE⊥BC,DF⊥BC,垂足分别为E,F.CE=BF,求证AB‖CD.