AB=CD,AE垂直BC,DF垂直BC,CE=BF,求证AE=DF

AB=CD,AE垂直BC,DF垂直BC,CE=BF,求证AE=DF 11.214页练习的第2题：AB=CD,AE垂直于BC,DF垂直于BF,CE=BF,求证AE=DF 如图，AB=CD，AE⊥BC，DF⊥BC，CE=BF．求证：AE=DF． ab=cd,ae垂直于e,df垂直于bc于f,ad交ed于o,oa=od,求证：bf=ce 如图,已知,AB=CD,AE⊥BC于E点,DF⊥BC于F,AE=DF,求证CE=BF 如图,AB=CD,AE⊥BC,DF⊥BC,垂足分别为E,F,CE=BF.求证AE=DF 如图,在平行四边形ABCD中,BC=2AB,AE=AB=BF,且点E.F在直线AB上,求证：CE垂直DF 如图,在平行四边形ABCD中,BC=2AB,AE=AB=BF,且点F在直线AB上,求证CE垂直DF 在平行四边形ABCD中,BC=2AB,AE=AB=BF,且E,F在直线AB上,求证：CE垂直于DF. 如图,AB=CD,AE=DF,CE=BF,求证AE平行DF 如图所示,AB=CD,AE=DF,CE=BF,求证 AE‖DF 如图,AB=CD,AE=DF,CE=BF,求证：AE平行DF