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初一数学题(x+2y)^2(x^2+4y^2)^2(x-2y)^2-[X^4-(2y^4)^2]^2

来源：学生作业帮 编辑：神马作文网作业帮 分类：数学作业 时间：2024/11/16 10:32:18
初一数学题(x+2y)^2(x^2+4y^2)^2(x-2y)^2-[X^4-(2y^4)^2]^2
(x+2y)^2(x^2+4y^2)^2(x-2y)^2-[X^4-(2y^4)^2]^2要步骤
初一数学题(x+2y)^2(x^2+4y^2)^2(x-2y)^2-[X^4-(2y^4)^2]^2
(2y^4)^2应该是(4y^2)^2
原式=[(x+2y)(x-2y)]^2(x^4+4y^2)]^2-(x^4-16y^4)^2
=(x^2-4y^2)^2(x^4+4y^2)]^2-(x^4-16y^4)^2
=(x^4-16y^4)^2-(x^4-16y^4)^2
=0
x^2-y^2/x+y-4x(x-y)+y^2/2x-y, 数学题……555{(3x+y)(3x-y)-(x-5y)(5x-y)-(x-2y)²÷(-4x),x=-2.y (2x-y)^2-4(x-y)(x+2y) (2x-y)²-4(x-y)(x+2y) 化简：（2x-y)²-4(x-y)(x+y) {(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y x+2y+4y^2/x-y+4x^y/4y^2-x^2 4x(y-x)-y^2因式分解 (x+3y-4)(2x-y) x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2 1、x(x-y)(x+y)-x(x+y)^2 1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [（x+y)(x-y)-(x-y)^2+2y(x-y