用拆项法解决:(-2010又5/6)+(-2011又2/3)+4022+(-1又1/2)
初一数学2008又5/6+(-2009又3/4)-2010又1/2+2011又2/3
计算2009又1/2+(-2010又5/6)+(-2011又2/3)+2012又1/3+(-1又1/2)
(-1000又2/3)+(-999又5/6)+2000又3/4+(-1又1/2)
-5又1/3+2又11/12-16又1/4-3又5/6
3又(1/3) +5又(2/4) +7又(3/5) +9又(4/6) 分之 1又(2/3)+ 2又(3/4)+ 3又(4
-2000 又2/3+(-1999又3/4)+4000又5/6+(-1又1/3) 用拆项法计算
(-2005又5/6)+(-2004又2/3)+4010又2/3+(-1又1/2)
(-2000又5/6)+(-1999又2/3)-(-4000又3/4)-(+1又1/2)
计算3又3/4-8又1/6-(2又1/2)-1又5/6.
简算:6又3/11/(1又5/7*1.48)*2.96/2又1/11/1又1/6
-2006又5/6+(-1999又2/3)+4000又3/4+(-1又1/2)
1又1/2+2又1/6+3又1/12+4又1/20+5又1/30+6又1/42+7又1/56+8又1/72+9又1/90