求证 sin(x+π/3)-√3cos(2π/3-x)+2sin(x-π/3)=0
求证 tan(2π-X)sin(-2π-X)cos(6π-X)/ sin(X+3π/2)*cos(X+3π/2)=-ta
已知函数f(x)=(√3sinωx+cosωx)*sin(-3π/2+ωx)(0
三角等式求证:cos^6x+sin^6x=1-3sin^2x+3sin^4x
f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx
已知函数f(x)= [sin(2π-x)sin(π+x)cos(-x-π)] /[2cos(π-x)sin(3π-x)]
已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x
已知函数f(x)=cos(2x-π\3)+sin²x-cos²x
已知函数f(x)=2cos(x-π/6)sin(x+π/6)-√3*(sin(x-π/6))^2+sin(x-π/6)c
已知f(x) =sin^2 x +2sinx cos x + 3 cos^2 x ,x∈(0 ,π) .
求导f(x) = cos(3x) * cos(2x) + sin(3x) * sin(2x).
sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1