sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/11 17:04:47

sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
求化简过程.

原式=sin（x+π/3）+√3cos（x+π/3）+2sin（x-π/3）
=2[1/2sin(x+π/3)+√3/2cos(x+π/3)]+2sin(x-π/3)
=2sin(x+π/3+π/6)+2sin(x-π/3)
=2[sin(x+π/2)+sin(x-π/3)]
=2(cosx+√3/2sinx-1/2cosx)
=2(√3/2sinx+1/2cosx)
=2sin(x+π/6)

sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x) 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 已知函数f(x)=sin^2*x-根号3*sinπ/4*x*cosπ/4*x 已知函数f(x)=sin²ωx+根号3sinωx乘sin(ωx+π/2)+2cos²ωx,x∈R,（求化简f(x)=sin^2x+2根号3sin(x+π/4)cos(x-π/4)-cos^2x-根号3 f(x)=sin平方x+2根号3sin(x+π/4)cos(x-π/4)-cos平方x-根号3 化简 1/2cos x-根号3/2sin x 根3sin x+cos x Sin(x+π/3)+2Sin(x-π/3)-根号3乘以Cos(2π/3 -x ) 化简化简 2sin(2πx)cos(2πx)+根号（3）sin(2πx)=0 0 已知sin(x+π/3)cos(x-π/3)+cos(x-π/3)sin(x-π/3)=-(2根号2/3)且π 根号3sin x+cos x要化简化简sin(π+π/3)+2sin(x-π/3)-根号下3 *cos(2π/3-x)