int j,a[]={1,3,5,7,9,11,13,15,
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int j,a[]={1,3,5,7,9,11,13,15,
#include
main()
{ int j,a[]={1,3,5,7,9,11,13,15},*p=a+5;
for(j=3; j; j--)
{ switch(j)
{ case 1:
case 2:printf("%d",*p++); break;
case 3:printf("%d",*(--p));
}}}
答案是9911,是怎样来?
#include
main()
{ int j,a[]={1,3,5,7,9,11,13,15},*p=a+5;
for(j=3; j; j--)
{ switch(j)
{ case 1:
case 2:printf("%d",*p++); break;
case 3:printf("%d",*(--p));
}}}
答案是9911,是怎样来?
j=3时执行case 3: printf("%d",*(--p));(循环前p指针指向a[5])这时指向a[4];访问a[4]的值为9;
int j,a[]={1,3,5,7,9,11,13,15,
#include main() { int j,a[]={1,3,5,7,9,11,13,15},*p=a+5; for
#include main() { int j,a[ ]={1,3,5,7,9,11,13,15},*p=
int j;int x[3][3]={1,2,3,4,5,6,7,8,9}; for (j=2; j>=0; j--)
struct { int i ,j ,k; } a[3]={1,2,3,4,5,6,7,8,9}; cout
char c='A'; for(int j=7;j>=0;--j) coutj&1);
#include int main() { int a[3][4]={1,3,5,7,9,11,13,15,17,19,
下面语句执行后,i 的值是( B ).for( int i=0,j=1; j < 5; j+=3 ) i=i+j; A)
#include void main() { int i,j; int a[3][3]={{0,1,2},{3,4,5}
for( int i=0,j=1; j < 5; j+=3 ) i=i+j; 为什么等于5
int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int **p; p=(int**)a;
假如有int i=1,j=7,a;a=i+j%4!=0;则a=