struct { int i ,j ,k; } a[3]={1,2,3,4,5,6,7,8,9}; cout
struct { int i ,j ,k; } a[3]={1,2,3,4,5,6,7,8,9}; cout
Struct Struct st {int x;int *y;}*pt; Int a[]={1,2},b[]={3,4}
int i,j,t,k,与int i,j,t,k,a[0,1,2,3,4];的区别
int i=2,j=1,k=3 i&&(i+j)&k|i+j
main() { int i=3,j=2,k; k=i+j; { int k=8; if(i=4) printf("%d
int j;int x[3][3]={1,2,3,4,5,6,7,8,9}; for (j=2; j>=0; j--)
设int i=0,j=1,k=2,a=3,b=4,c=5;
int a=5;b=3;cout
struct st{int x;int*y;}*p;inta[]={1,2},b[]={3,4};struct st c
设int i=0,j=1,k=2,a=3,b=4,c=5; 执行表达式(a=ik)&&(c=i,j,k)后,a,b,c的
刚学的C语言struct stint i;int j;int *q;main(){struct m[]={{10,1},
int i=2,j=3,k=4,a=4,b=5,c=6,则执行表达式(a=ik)&&(c=i,j,k)后,c的值是