1/2(lg2)^2+1/2lg2*lg5+√1/4(lg2)^2-lg2+1=?
1/2(lg2)^2+1/2lg2*lg5+√1/4(lg2)^2-lg2+1=?
lg5*(1+lg2)+(lg2)^2=
2(lg2)2+lg2•lg5+(lg2)2-lg2+1=lg2(2lg
lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5
lg2(1+lg5)+(lg5)^2
(lg2)2[2lg5+1]+(lg5)2[2lg2+lg10]
lg2+1/2lg5/2
1 (lg5)^2+lg50*lg2
高一数学(2+lg2+1)lg5+(2+lg2)lg2=?
(lg2^2+1)(lg2)^2+1=?
lg25+lg2*lg50+(lg2)^2+1=?
(lg2)的平方+lg2∙lg5+2分之1lg25