sin(x+π/6)=1/2,求cos(π/3-x)
化简:1、sin(x-π/3)-cos(x+π/6)+√3cosx=?2、已知,sinα+sinβ=√2/2,求cosα
sin(x+π/6)=1/2,求cos(π/3-x)
已知f(x)=-1/2+sin(π/6-2x)+cos(2x-π/3)+cos²x,(1)求f(x)的最小正周
已知cos(π/2+x)=sin(x-π/2) 求sin^3(π-x)+cos(x+π)/5cos(5π/2-x)+3s
已知函数fx=sin(2x-π/3)+cos(2x-π/6)+2cos²x-1,x∈R. 1.求函
已知·函数f(x)=sin(2x-3/π)+cos(32x-6/π)+2cos²x-1 求函数的最小正周期
已知f(x)=-1/2+sin(π/6-2x)+cos(2x-π/3)+cos平方x.
Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y)
求下列函数的奇偶性f(x)=(1+sin x-cos x)/(1+cos x+sin x),x属于[(-π/2),(π/
求y=sin(2x+π/3)+cos(2x-π/6)的单调区间
求函数f(x)=sin(π/3+4x)+cos(4x-π/6
已知f(x)=cos^2x/1+sin^2x求f'(π/4)