(3)3M-[2N-(2M-3N)-N]

[(m-n)^2*(m-n)^3]^2/(m-n)^4 （m-n)2(n-m)3(n-m)4化简 计算(m+n)^3-(n+m)(m-n)^2 （n-m)^3×(m-n)^2-(m-n)^5 因式分解(n-m)^3(m-n)^2-(m-n)^5 3m(m-n)-2n(m-n)的平方 已知3m=2n,则m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=? 初一计算：(m+5n)(m-n)-6(m+2n)(n-3n)? (3)3M-[2N-(2M-3N)-N] 已知m/n=5、,求（m/（m+n）)+(m/(m-n))-(n^2/(m^3-n^2)) (2m+3n)(2m-3n)-(3m-2n)(3m+2n) (2m+3n)(3m-2n)-(3m-2n)(3m+2n)