如图,已知△ABC中,∠BAC=90°,AD⊥BC,EF⊥BC,FM⊥AC,垂足分别为DFM,∠1=∠2,试说明FM=F
如图,已知△ABC中,∠BAC=90°,AD⊥BC,EF⊥BC,FM⊥AC,垂足分别为DFM,∠1=∠2,试说明FM=F
如图所示,△ABC中,∠BAC=90°,AD⊥BC,EF⊥BC,FM⊥AC,垂足分别为DFM,∠1=∠2.求证:FM=F
如图所示,已知△ABC中,∠BAC=90°,AD⊥BC,EF⊥BC,FM⊥AC,∠1=∠2,求证:FM=FD
如图所示,已知△ABC中,∠BAC=90°,AD⊥BC,EF⊥BC,FM⊥AC,∠1=∠2,求证FM=FD
△ABC中,∠BAC=90°,AD⊥BC,EF⊥BC,FM⊥AC,垂足分别是D,F,M,∠1=∠2,求证FM=FD
如图,已知:在△ABC中,∠BAC+90°,AD⊥BC,EF⊥BC,FM⊥AC,∠1=∠2求证:FM=FD
如图,在△ABC中,∠BAC=90°,BE平分∠ABC交AC于E,AD⊥BC,EF⊥BC,FM⊥AC,垂足分别是D,F,
如图,在△ABC中∠BAC=90°,AD⊥BC,EF⊥BC,FM⊥AC.垂足分别是D,F,M.∠1=∠2.
△ABC中,∠BAC=90°,AD⊥BC,EF⊥BC,FM⊥AC,垂足平分线D、F、M,∠1=∠2.求证:FM=FD
△ABC中,∠BAC=90°,AD⊥BC,EF⊥BC,FM⊥AC,垂足平分线D、F、M,∠1=∠2.求证:FM=FD
=如图,在△ABC中,∠BAC =90°,EF⊥BC,AD⊥BC,FM⊥AC,∠1=∠2,求证:FM=FD
如图,在△ABC中,∠BAC=90°,BE平分∠ABC交AC于E,AD⊥BC,EF⊥BC,FM⊥AC,求证:FM=FD