国外的物理题Consider the setup of a gun aimed at a target located
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国外的物理题
Consider the setup of a gun aimed at a target located at the point A. At t = 0 the gun is fired at the same time the target is dropped from A. The bullet hits the target at a point P which is along the vertical line AB. Let the initial speed of the bullet be vo = 136 m/s and the angle between the vector ~v0 and the x-axis be θ = 53.4◦and AB = 97.6 m. The distance OB is the x-coordinate of the target. The acceleration of gravity is 9.8 m/s2 .Determine the height of BP. Answer in units of m.
抱歉各位 没有崇洋媚外的意思 只是怕我翻译的不好 让大家误解了原题目的意思。。。
那我就试着翻译下:
某人在O点处朝A点处的目标开枪,开枪的同时目标从A点处垂直往下掉。子弹在P点处击中目标(P点是垂直线AB某一点位置) 子弹的初速度是136米每秒而且与X轴的角度是53.4度 AB=97。6米 OB是枪与目标的水平距离。。 重力加速度=9.8m/s^2 求BP的高度。
Consider the setup of a gun aimed at a target located at the point A. At t = 0 the gun is fired at the same time the target is dropped from A. The bullet hits the target at a point P which is along the vertical line AB. Let the initial speed of the bullet be vo = 136 m/s and the angle between the vector ~v0 and the x-axis be θ = 53.4◦and AB = 97.6 m. The distance OB is the x-coordinate of the target. The acceleration of gravity is 9.8 m/s2 .Determine the height of BP. Answer in units of m.
抱歉各位 没有崇洋媚外的意思 只是怕我翻译的不好 让大家误解了原题目的意思。。。
那我就试着翻译下:
某人在O点处朝A点处的目标开枪,开枪的同时目标从A点处垂直往下掉。子弹在P点处击中目标(P点是垂直线AB某一点位置) 子弹的初速度是136米每秒而且与X轴的角度是53.4度 AB=97。6米 OB是枪与目标的水平距离。。 重力加速度=9.8m/s^2 求BP的高度。
Vx=136*COS 53.4°=81.08M/S
Vy=136*SIN 53.4°=109.2M/S
BP=(109.2-gt+109.2)t/2
AP=1/2gt^2
AP+BP=AB=97.6M
(109.2-gt+109.2)t/2 + 1/2gt^2=97.6
g=9.8
109.2t=97.6
t=97.6/109.2
BP=109.2t-1/2gt^2=97.6-3.9=93.7M
Vy=136*SIN 53.4°=109.2M/S
BP=(109.2-gt+109.2)t/2
AP=1/2gt^2
AP+BP=AB=97.6M
(109.2-gt+109.2)t/2 + 1/2gt^2=97.6
g=9.8
109.2t=97.6
t=97.6/109.2
BP=109.2t-1/2gt^2=97.6-3.9=93.7M
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