求输出结果?main() int a=1,b=2;a=a+b;b=a-b;a=a-b;printf(“%d,%d\n”,
求输出结果?main() int a=1,b=2;a=a+b;b=a-b;a=a-b;printf(“%d,%d\n”,
int a=2,b=3; printf(a>b?”***a=%d”:”###b=%d”,a,b); 求结果,
#include void main() { int a=21,b=11; printf("%d\n",--a+b,--
main() {int a=666,b=888; printf("%d\n",a,b) }
# include main() { int a=-2,b=0; while(a++&&++b); printf("%d
{int **k,*k,b=100; a=&b;k=&a;printf("%d\n",**k);} 输出结果.
若定义:int a=511,*b=&a;,则printf("%d\n",*b);的输出结果为 ( ).
我想知道main() {int a=1,b=2,c=3; printf(“%d,%d,%d,%d\n",a=b=c,a=
void main() { int a,b; printf("enter a:"); scanf("a=%d",&a);
#include main() {int a=2,b=2,c=2; printf("%d\n",a/b&c); } 答案
以下程序的输出结果是 main() { int a=21,b=11; printf("%d\n",- -a+b,- -b
void main( ) { int a=5,b=8; printf(“a=%d b=%d\n”,a,b) ; a=a+