(1)0.4-(-4/1)+6/1(2)3/1-(-6/5)+3/2(3)3/1+(-5/1)+1+3/2(4)27-1
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/20 06:55:15
(1)0.4-(-4/1)+6/1(2)3/1-(-6/5)+3/2(3)3/1+(-5/1)+1+3/2(4)27-18+(-7)-32
(5)0.5+(-4/1)-(2.75)+2/1(6)33.1-(-22.9)+(-10.5)(7)(-8)-(-15)+(-9)-(-12)(8)-3/2+(-6/1)-(-4/1)-2/1(9)5/3-2/3+(-4/11)+4/13
(5)0.5+(-4/1)-(2.75)+2/1(6)33.1-(-22.9)+(-10.5)(7)(-8)-(-15)+(-9)-(-12)(8)-3/2+(-6/1)-(-4/1)-2/1(9)5/3-2/3+(-4/11)+4/13
(1)0.4-(-4/1)+6/1
=0.4+1/4+1/6
=24/60+15/60+10/60
=49/60 (六十分之四十九)
(2)3/1-(-6/5)+3/2
=1/3+5/6+2/3
=2/6+5/6+4/6
=11/6(六分之十一)
(3)3/1+(-5/1)+1+3/2
=1/3-1/5+1+2/3
=5/15-3/15+15/15+10/15
=27/15(十五分之二十七)
(4)27-18+(-7)-32
=27-18-7-32
=-30
(5)0.5+(-4/1)-(2.75)+2/1
=0.5-0.25-2.75+0.5
=-2
(6)33.1-(-22.9)+(-10.5)
=33.1+22.9-10.5
=45.5
(7)(-8)-(-15)+(-9)-(-12)
=-8+15-9+12
=10
(8)-3/2+(-6/1)-(-4/1)-2/1
=-2/3-1/6+1/4-1/2
=-8/12-2/12+3/12-6/12
=-13/12(负十二分之十三)
(9)5/3-2/3+(-4/11)+4/13
=3/5-3/2-11/4+13/4
=12/20-30/20-55/20+65/20
=-8/20
=-2/5(负五分之二)
=0.4+1/4+1/6
=24/60+15/60+10/60
=49/60 (六十分之四十九)
(2)3/1-(-6/5)+3/2
=1/3+5/6+2/3
=2/6+5/6+4/6
=11/6(六分之十一)
(3)3/1+(-5/1)+1+3/2
=1/3-1/5+1+2/3
=5/15-3/15+15/15+10/15
=27/15(十五分之二十七)
(4)27-18+(-7)-32
=27-18-7-32
=-30
(5)0.5+(-4/1)-(2.75)+2/1
=0.5-0.25-2.75+0.5
=-2
(6)33.1-(-22.9)+(-10.5)
=33.1+22.9-10.5
=45.5
(7)(-8)-(-15)+(-9)-(-12)
=-8+15-9+12
=10
(8)-3/2+(-6/1)-(-4/1)-2/1
=-2/3-1/6+1/4-1/2
=-8/12-2/12+3/12-6/12
=-13/12(负十二分之十三)
(9)5/3-2/3+(-4/11)+4/13
=3/5-3/2-11/4+13/4
=12/20-30/20-55/20+65/20
=-8/20
=-2/5(负五分之二)
(1)0.4-(-4/1)+6/1(2)3/1-(-6/5)+3/2(3)3/1+(-5/1)+1+3/2(4)27-1
计算(1)-2.5+(-1/5); (2)0.4-(-1/4)+1/6(2)1/3-(-5/6)+2/3; (4)1/3
(1+2/1)(1+4/1)(1+6/1).(1+10/)(1-3/1)(1—5/1).(1-9/1)
(1+1/2)*(1+1/4)*(1+1/6)*...*(1+1/2008)*(1-1/3)*(1-1/5)*(1-1/
1/(1*3)+1/(2*4)+1/(3*5)+1/(4*6)+...+1/(8*10)=?
1/6【1/4{1/3(1/2X-1)+3}+5】=1
1.动脑筋计算:(1+1/2)*(1+1/4)*(1+1/6)*…* (1+1/10)*(1-1/3)*(1-1/5)*
(-1/4)+5/6+2/3-1/2
巧算:(1/2+1/3)-(1/3+1/4)+(1/4+1/5)-(1/5-1/6)-(1/6+
1/2*1/3+1/3*1/4+1/4*1/5+1/5*1/6 (简便方法)
(1-3/(2*4))×(1-3/(3*5))×(1-3/(4*6))×.×(1-3/(97*99))=?
1/(1+2+3)+1/(4+5+6)+.+1/(100+101+102) =?