求导dy/dx:y=(4+x^2)(arctan x/2)

求导dy/dx:y=(4+x^2)(arctan x/2) 函数y=arctan(1+x^2)求dy/dx y=lnsin^2x 求导 Dy/Dx 设ln(x^2+y^2)=arctan(y/x),则dy/dx= x^2+y^2=e^(arctan（y/x）),求dy/dx arctan(y/x)=ln(sqrt(x^2+y^2)),请问dy/dx是什么? ln√(x^2+y^2)=arctan(y/x)的导数dy/dx 计算I=∮1/x*arctan(y/x)dx+2/y*arctan(x/y)dy,L为圆周x^2+y^2=1,x^2+y y^3+4y^2+11y=x-13 求导 dy/dx 怎么求呀? 设函数y=arctan(1+x^2),求dy/dx. 求导数高数作业ln√（x∧2+y∧2）＝arctan（y╱x）求dy╱dx 已知函数y=x(x-1)(x-2)(x-3)求导数值dy/dx ,