SAT数学题求讲解1.On a certain number line,if -7 is a distance of 4
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SAT数学题求讲解
1.On a certain number line,if -7 is a distance of 4 from n and 7 is a distance of 18 from n,then n =
A 25 B 11 C 3 D -3 E -11
2.If y = a/a+b and x = a/b,what is y in terms of x
A - 1/x B 1+x C 1 + 1/x D 1/1+x E x/1+x
答案两题都是E,求讲解
1.On a certain number line,if -7 is a distance of 4 from n and 7 is a distance of 18 from n,then n =
A 25 B 11 C 3 D -3 E -11
2.If y = a/a+b and x = a/b,what is y in terms of x
A - 1/x B 1+x C 1 + 1/x D 1/1+x E x/1+x
答案两题都是E,求讲解
第一题,若-7到n这点的距离是4,并且7到n这点的距离是18,那么n等于多少?
答案很显然吧,是-7-4=-11
第二题,1/y=1+b/a
所以1/y=1+1/x
即y=x/(1+x)
再问: 第二题为什么1/y=1+1/x 所以y=x/(1+x)
再答: y = a/(a+b)
两边同时取倒数,1/y=(a+b)/a
即1/y=1+b/a
即1/y=1+1/x
然后,1/y=(1+x)/x
两边取倒数,y=x/(1+x)
答案很显然吧,是-7-4=-11
第二题,1/y=1+b/a
所以1/y=1+1/x
即y=x/(1+x)
再问: 第二题为什么1/y=1+1/x 所以y=x/(1+x)
再答: y = a/(a+b)
两边同时取倒数,1/y=(a+b)/a
即1/y=1+b/a
即1/y=1+1/x
然后,1/y=(1+x)/x
两边取倒数,y=x/(1+x)
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