[(2x+y)(x-3y)+y(x+3y)]÷(2x)计算,
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[(2x+y)(x-3y)+y(x+3y)]÷(2x)计算,
(2x+y)(x-3y)=2x(x-3y)+y(x-3y);y(x-3y)+y(x+3y)=2xy;所以2x(x-3y)+2xy=2x(x-3y+y)=2x(x-2y);
2x(x-2y)÷(2x)=x-2y
再问: 能连住写下吗?这样还不太清楚
再答: [(2x+y)(x-3y)+y(x+3y)]÷(2x) =[2x(x-3y)+y(x-3y)+y(x+3y)]÷(2x) =[2x(x-3y)+y(x-3y+x+3y)]÷(2x) =[2x(x-3y)+2xy]÷(2x) =x-3y+y或者=[2x(x-3y+y)]÷2x =x-2y
2x(x-2y)÷(2x)=x-2y
再问: 能连住写下吗?这样还不太清楚
再答: [(2x+y)(x-3y)+y(x+3y)]÷(2x) =[2x(x-3y)+y(x-3y)+y(x+3y)]÷(2x) =[2x(x-3y)+y(x-3y+x+3y)]÷(2x) =[2x(x-3y)+2xy]÷(2x) =x-3y+y或者=[2x(x-3y+y)]÷2x =x-2y
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