int x,y,z; x=2; y=4; z=7; x=y--
int x,y,z; x=2; y=4; z=7; x=y--
fun(int x,int *y) { int z; x-=2;(*y)++; z=x%(*y); return z;
int max(int x,int y) { int z; if(x>y) z=x; else z=y; return(
(x+y-z)(x-y+z)=
fun(int x,int y,int z) {z=x*x+y*y;} main() {int a=31; fun(5,
1)int z=5;f ( ){ static int x=2; int y=5;x=x+2; z=z+5;y=y+z;
int x=1,y=2,z=3; x=x^z; y=y^z; z=x^y; cout
若已定义int x,y,z 执行语句x=(x=1,y=z=2,y++,z++),x,y,z的值分别是
int x=3,y=2,z=1;printf("%d\n",x/y&~z)
X+Y+Z=?
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
C语言:int x=5,y=7,z; z=x>y?5>3?++x+y:x:++x-y++ 则z的值为________.