如图,△ABC中,AB=AC,AB+AC=BD+DC,AC、BD交于O；求证：OA>OD

如图,△ABC中,AB=AC,AB+AC=BD+DC,AC、BD交于O；求证：OA>OD 如图,在等腰梯形ABCD中,AB∥DC,AC、BD交于点O.求证：OD=OC 如图,已知等腰梯形ABCD中,AB∥DC,AC,BD,交于点O求证；OD=OC. 如图,AC和BD相交于点O,且AB平行DC,OC=OD,求证：OA=OB 如图：AC和BD相交于点O,OA=OC,OB=OD,求证：DC//AB 如图,AB,CD相交于点O,AC||BD,求证OA*OD=OB*OC 已知：如图,AC和BD交于点O,AB//CD,OA=OB 求证OC=OD 如图,△ABC与△DCB的顶点A和D在BC的同侧,AB=DC,AC=BD,AC与BD相交于点O,求证：OA=OD 如图,在△ABC和△DCB中,AC与BD相交于点O,AB=DC,AC=BD,求证:△ABC≌△DCB. 如图：△ABC和△DCB中,AC与BD相交于O,AB=DC,AC=BD. 如图,三角形ABC与DCB的顶点在A和D在BC的同侧,AB=DC,AC=BD,AC与BD相交于点O,求证：OA=OD 如图所示,在梯形ABCD中,AB‖DC,AD=BC,AC与BD交于点O,求证:OA=OB,OD=OC