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tanπ/12-cotπ/12

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tanπ/12-cotπ/12
tanπ/12-cotπ/12
=sinπ/12/cosπ/12-cosπ/12/sinπ/12
=(sin²π/12-cos²π/12)/(sinπ/12cosπ/12)
=-cos(2*π/12)/[1/2*sin(2*π/12)]
=-cosπ/6/(1/2*sinπ/6)
=-2√3
tanπ/12-cotπ/12 tanπ/12+cotπ/12的值等于多少? 求tanπ/8 + cotπ/12的值 tan(π/8)-cot(π/8)=? tan(-a+3/2π）/cot(-a-π) tanα=-cotθ θ属于(π/2,π) tan(3/2π-α)=?；cot(-α-π)=? tan(π/4-a)=cot(π/4+a) 1)求证cotαcosα/cotα-cosα=tan(α/2+π/4) cot(π/2+α)=tanα吗 化简:tan派/8+cot派/12=? 化简sin(3π+a)tan(a-π）cot(π+a)/tan(2π-a)cos(π-a)