已知x2+y2-10x-6y+34=0,求y\x+y的值

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$已知x2+y2-10x-6y+34=0,求y\x+y的值$

x²＋y²－10x－6y＋34=0,即(x－5)²＋(y－3)²=0,所以,x=5,y=3,所以(x＋y)/y=(5＋3)/3=8/3

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