(p-2q)^2-2(p+2q)(p+3q)+(p+3q)^2
(p+2q)(2p-q)-(p+q)(p-q)
因式分解(p+2q)^2-2(p+2q)(p+3q)+(p+3q)^2
(p-2q)^2-2(p+2q)(p+3q)+(p+3q)^2
因式分解(2p+q)(8p-3q)-2p(2p+q)
先化简再求值:(p+2q)^2-2(p+2q)(p+3q)+(p+2q)(3q-p),其中p=-1,q=-2
6(p+q)^-2(p+q)
将[(p-q)³-2(q-p)²-2/3(q-p)]/ p-q/3(p≠q)化归为关于p、q的多项式
4(2p+3q)^2 -(3p-q)^2
4(2p+3q)^2 - (3p-q)^2
因式分解p^3-p^2q-pq^2+q^3
已知p^3+q^3=2,求证p+q
(3p+2q)乘以(p+4q)等于多少