x+a%3*(int)(x+y)%2/4 设x=2.5 a=7 y=4.7
x+a%3*(int)(x+y)%2/4 设x=2.5 a=7 y=4.7
求算术表达式x+a%3*(int)(x+y)%2/4的值,设x=2.5,a=7,y=4.7中a%3*(int)(x+y)
设X=2.5,a=7,y=4.7,表达式x+a%3*(int)(x+y)%2/4的值是?
C语言中的算数表达式设x=2.5,a=7,y=4.7 则x+a%3*(int)(x+y)%2/4的值为多少?
c语言中x+a%3*(int)(x+y)%2/4 x=2.5 a=7 y=4.7
已知:a=7,x=2.5,y=4.7(a整型,x,y浮点),计算算术表达式x+a%3*(int)(x+y)%2/4的值.
设x=2.5 a=7 c=4.7,算术表达式x+a%3*(int)(x+y)%2/4的值是?
int a=7;float x=2.5,y=4.7 x+a%3*(int)(x+y)%2\4的值为什么等于2.5
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若有定义“int a=7;float x=2.5,y=4.7;”,则表达式x+a%3*(int)(x+y)%2/4的值是
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