以知m^2+9n^2+6m+6n+10=0,求(m^2-6mn+9n^2)除以(m-3n)-(4m^2-9n^2)除以(
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以知m^2+9n^2+6m+6n+10=0,求(m^2-6mn+9n^2)除以(m-3n)-(4m^2-9n^2)除以(2m-3n)的值
28/37
再问: 请说明过程
再答: 已知:m^2+9n^2+6m+6n+10=(m+3)^2+(3n+1)^2=0 由于(m+3)^2>=0,(3n+1)^2>=0 则m=-3,n=-1/3, (m^2-6mn+9n^2)=(m-3n)^2=4 (m-3n)-(4m^2-9n^2)=-2-(2m-3n)(2m+3n)=-2-35=-37 2m-3n=-7 4/(-37(/(-7)=28/37
再问: 请说明过程
再答: 已知:m^2+9n^2+6m+6n+10=(m+3)^2+(3n+1)^2=0 由于(m+3)^2>=0,(3n+1)^2>=0 则m=-3,n=-1/3, (m^2-6mn+9n^2)=(m-3n)^2=4 (m-3n)-(4m^2-9n^2)=-2-(2m-3n)(2m+3n)=-2-35=-37 2m-3n=-7 4/(-37(/(-7)=28/37
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