y=f(x^2+1),且f'(x)=x^2,则dy/dx | x=-1=?
y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy
若df(x,y)=(2x-y)dx+(2y-x)dy 且f(0,0)=1 试求函数f(x,y)
y=f(x^2+1),且f'(x)=x^2,则dy/dx | x=-1=?
设f(x)可导,且f'(0=1,又y=f(x^2+sin^2x)+f(arctanx),求dy/dx /x=0
f(x)为连续函数,∫(1-2)f(x)dx=1,F(t)= ∫(1-t)[f(y) ∫(y-t)f(x)dx]dy,则
设y=f^2(3x-2/3x+2),f(x)=In(1+x^2),则dy/dx|x=0=?
设f(x)在【0,1】上连续且∫(0,1)f(x)dx=A,证明∫(0,1)dx∫(x,1)f(x)f(y)dy=A∧2
函数y=f(sin^2(x)),f'(X)=g(x),则dy/dx=?
F(t)=∫上标t下标1dy∫上标t下标y f(x)dx,且f(x)为连续函数则F'(2)=?
设f(x)=1/x,y=f[(x-1)/(x+1)],求dy/dx
如果f'(x)=sin x^2 ,y=f(2x/x-1),求dy/dx
∫(上1下0)dx∫(上x下x^2)f(x,y)dy=?