x=1 y=2 do x=x*y y=y+1 loop while y

x=1 y=2 do x=x*y y=y+1 loop while y X=2 Y=4 Do x=x*y y=y+1 Loop While y x=5,y=110{x=y/x; y=y-x;}while(y>=1); 求x y 先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y 执行下列程序段后,y的值是() int x=1,y=5; do{y-=x;++x;} while(--y (3x-y)^2+(3x+y)(3x-y),x=1,y=-2 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 已知4x=9y求(1)x+y/y (2)y-x/2x x=0 y=0 do while x 设有整型变量x和y的值分别为5和110.do{x=y/x; y=y-x;}while(y>=1); 结果是x=18; y 2(x+y) 3x+3y=24 x+y/2x x y/2y= 1 VFP do while程序 Y=X%10+Y*10 x=int(x/10)