请matlab高手来帮忙 自变量x取值范围[60°,130°],y=arccos((129.6+188.16cos(x)
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/19 22:04:20
请matlab高手来帮忙 自变量x取值范围[60°,130°],y=arccos((129.6+188.16cos(x)-155.82sin(x))/250.9)
z=2arctan((-6.5sin(y)+14.7sin(x)+4.370746)/(12.23271-6.5cos(y)+14.7cos(x)))
t=19.3cos(z)+1.6746(19.3cos(z)-14.7cos(x)+7.06729)
求t-x变化曲线
如果z=2arctan((-6.5sin(y-z)+14.7sin(x)+4.370746)/(12.23271-6.5cos(y-z)+14.7cos(x)))
z=2arctan((-6.5sin(y)+14.7sin(x)+4.370746)/(12.23271-6.5cos(y)+14.7cos(x)))
t=19.3cos(z)+1.6746(19.3cos(z)-14.7cos(x)+7.06729)
求t-x变化曲线
如果z=2arctan((-6.5sin(y-z)+14.7sin(x)+4.370746)/(12.23271-6.5cos(y-z)+14.7cos(x)))
x=60:130;
x=x/180*pi;
y=acos((129.6+188.16.*cos(x)-155.82.*sin(x))/250.9);
z=2*atan((-6.5.*sin(y)+14.7.*sin(x)+4.370746)/(12.23271-6.5.*cos(y)+14.7.*cos(x)));
t=19.3.*cos(z)+1.6746.*(19.3.*cos(z)-14.7.*cos(x)+7.06729);
plot(x,t)
x=x/180*pi;
y=acos((129.6+188.16.*cos(x)-155.82.*sin(x))/250.9);
z=2*atan((-6.5.*sin(y)+14.7.*sin(x)+4.370746)/(12.23271-6.5.*cos(y)+14.7.*cos(x)));
t=19.3.*cos(z)+1.6746.*(19.3.*cos(z)-14.7.*cos(x)+7.06729);
plot(x,t)
请matlab高手来帮忙 自变量x取值范围[60°,130°],y=arccos((129.6+188.16cos(x)
y=arccos(-x)>π/4 则x的取值范围
y=-3/2cos(1/2x-π/6),x∈R当y为最大值时,自变量x的取值范围
函数y=根号(3-x)/x-1中,自变量x的取值范围
函数y=x+1分之根号2-x的自变量x的取值范围?
函数y=x 分之根号下x-3 中,自变量x的取值范围
函数y=x-1分之根号x+2中自变量x的取值范围?
在函数y=x+1/x+3中自变量x取值范围是什么
求函数y=x²-x-2自变量x的取值范围
函数y=2x-1分之x中自变量x的取值范围是
函数y=根号x-1\x-2自变量x的取值范围?
函数y=根号x-1/x-3自变量x的取值范围是