Sn=1x2+3x2^2+5x2^3+...+(2n-1)2^n
Sn=1x2+3x2^2+5x2^3+...+(2n-1)2^n
求和Sn=1x2+3x2^2+5x2^3+…+(2n-1)x2^n
Sn=1x2+3x2^2+5x2^3+…+(2n-1)x2^n sn=2sn-sn
Sn=1+3x2^2+5x2^3+.+(2n-1)x2^(n-1) 数列的.我知道用错项.我算出来是sn=5+(2n-3
1X2+2X2的2次方+3X2的3次方+(2n-1)X2的n次方
求和:Sn=1+3x+5x2+7x3+…+(2n-1)x(n-1)
用高中导数求和:Sn=1+2x+3x2+.+nx(n-1)
求和1x2+3x2^2+5x2^3+…+(2n-1)x2n要详解答案,我采纳!急用!
求和1x2+3x2^2+5x2^3+…+(2n-1)x2n要详解答案,急用!
x - x2/2!+ x3/3!+ ...+ (-1)n-1xn/n!
已知:M=3x2+2x-1,N=-x2-2+3x,求M-2N.
错位相减法求和:求和:Sn=1+3x+5x2+7x3+…+(2n-1)xn-1.