x-4根号(xy)-5y=0(根号x - 5根号y)(根号x+ 根号y)=0为什么
x-4根号(xy)-5y=0(根号x - 5根号y)(根号x+ 根号y)=0为什么
设x>0,y>0,且根号x(根号x+根号y)=3根号y(根号x+5根号y),求代数式2x+根号xy+2y\x-根号xy-
已知x、y满足根号下4x-5y+根号下x-y-1=0,则根号下xy-根号下x/y
根号x+根号y=根号5+3,根号xy=根号15-根号3,则x+y=?
已知根号x+根号y=根号5,根号xy=根号15-根号3,求x+y的值
已知x>0,y>0,x+根号xy-6y=0,求4x+5根号xy-6y分之x+2根号xy
已知x>0,y>0,且x+6y=5根号xy,求(2x+根号xy-y)分之(x+根号xy+2y)的值
若X2+Y+2x-4根号y+5=0,求根号xy
若x>o,y>o,且根号x(根号x+根号y)=3根号y(根号x+5根号y)求x+根号xy分之2x-根号xy-5y
已知x,y为正数,且根号x(根号x+根号y)=3根号y(根号x+5根号y),求:(2x+根号xy+3y)/(x+根号xy
{(x-y)/(根号x+根号y)}-(x+y-2倍根号xy)/(根号x-根号y)=?
若根号x-2+根号x+y-4=0,求xy+5的算术平方根.