Y=xloga(x^2+x-1) Y=log2((x-1)/(x+1)) 求导数,
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/18 18:33:23
Y=xloga(x^2+x-1) Y=log2((x-1)/(x+1)) 求导数,
Y=xloga(x^2+x-1) Y=log2((x-1)/(x+1))
求导数,
Y=xloga(x^2+x-1) Y=log2((x-1)/(x+1))
求导数,
1:
y'=x*[loga(x^2+x-1)]'+loga(x^2+x-1)
=x*(2x+1)/[lna*(-1 + x + x^2)]+loga(x^2+x-1)
=(2x^2+x)/[lna*(-1 + x + x^2)]+loga(x^2+x-1)
2:
y'=(x+1)/[Ln2(x-1)]*[(x - 1)/(x + 1)]'
=(x+1)/[Ln2(x-1)]*[(x+1)-(x-1)]/[(x+1)^2]
=2/[( x^2-1) Ln2]
y'=x*[loga(x^2+x-1)]'+loga(x^2+x-1)
=x*(2x+1)/[lna*(-1 + x + x^2)]+loga(x^2+x-1)
=(2x^2+x)/[lna*(-1 + x + x^2)]+loga(x^2+x-1)
2:
y'=(x+1)/[Ln2(x-1)]*[(x - 1)/(x + 1)]'
=(x+1)/[Ln2(x-1)]*[(x+1)-(x-1)]/[(x+1)^2]
=2/[( x^2-1) Ln2]