3x+6y-2z=-6

如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, 1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6 x+y+z=4 2x+3y-z=6 3x+2y+2z=10 2x-y+2z=-17 3x+y-3z=-4 x+y+z=6 2x+3y+z=11,3x+y-z=2,x+y+z=6求解 {2x+3y-4z=-5 x+y+z=6 x-y+3z=10 解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6} {x+y+z=6,2x-y+z=3,3x+9y+z=24 解方程{3x -y+z=4 2x+3y-z=12 x+y+z=6 已知x，y，z为实数，满足x+2y-z=6x-y+2z=3 解方程组：x+y+z=4,x+y+2z=5,3x+y-z=6 2x+5y+4z=6,3x+y-7z=-4,x+y-z=?