若1/x+2/y+z/3=4,3/x+2/y+1/z=6.则1/x+1/y+1/z=
若x-2y+4z=1,x+3y-7z=0,则y:z=?
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
3道高数题,1,函数F(x,y,z)=(e^x) * y * (z^2) ,其中z=z(x,y)是由x+y+z+xyz=
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
x+y+z=2 4x+2y+z=4 2x+3y+z=1
x+2y=3 x+y+z=36 2x+y+z=15 2y=3z x-y=1 x+2y+z x-z=-1 2x+z-y=1
如果,根号x-3+| y-2 |+z^2=2z-1 求 (x+z)^y
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
(x-2y+z)/9=(2x+y+3z)/10=-(3x+2y-4z)/3=1 连等,求x,y,z,
2x+3y+z=1 x+y+z=-2 3x-2y-z=-4 求x、y、z
若1/x+2/y+z/3=4,3/x+2/y+1/z=6.则1/x+1/y+1/z=
{5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-