2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/09/22 07:11:24
2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8
累死人的简便计算······
累死人的简便计算······
2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8
先乘出来,再合并
=2001/8-2001/2009+8/2001-8/2009-2009/8-2009/2001+8
=2001/8-2009/8-2001/2009-8/2009+8/2001-2009/2001+8
=(2001-2009)/8-(2001+8)/2009-(2009-8)/2001+8
=(-8)/8-(2009)/2009-(2001)/2001+8
=-1-1-1+8
=5
先乘出来,再合并
=2001/8-2001/2009+8/2001-8/2009-2009/8-2009/2001+8
=2001/8-2009/8-2001/2009-8/2009+8/2001-2009/2001+8
=(2001-2009)/8-(2001+8)/2009-(2009-8)/2001+8
=(-8)/8-(2009)/2009-(2001)/2001+8
=-1-1-1+8
=5
2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8
请问1÷(2÷3)÷(3÷4)÷(4÷5)÷...÷(2008÷2009)÷(2009÷2010)怎么做?
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8
计算2001*(1/8-1/2009) 8*(1/2001-1/2009) 2009*(1/8-1/2001)
2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8等于多少?
求2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8的简便方
1+1÷2+1÷4+1÷8+1÷16+1÷32+1÷64
2009÷2009 2009/2010+1/2011
2009÷2009 2009/2010--1/2011
1÷(2÷3)÷(3÷4)÷(4÷5)÷...÷(2008÷2009)÷(2009÷2010)怎么做